Y=10-2x/x^2

Solution for Y=10-2x/x^2 equation:

=10-2Y/Y^2

We move all terms to the left:

-(10-2Y/Y^2)=0


Domain of the equation: Y^2)!=0

Y!=0/1

Y!=0

Y∈R


We get rid of parentheses

2Y/Y^2-10=0

We multiply all the terms by the denominator


2Y-10*Y^2=0

We add all the numbers together, and all the variables

-10Y^2+2Y=0

a = -10; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-10)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-10}=\frac{-4}{-20}
=1/5
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-10}=\frac{0}{-20}
=0
$